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A processor accesses main memory with an average access time of T2. A smaller cache memory is interposed between the processor and main memory. The cache has a significantly faster access time of T1

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For any single memory access, the theoretical speedup to access a word stored in the cache rather than in main memory is given by:

[tex]Speedup=\frac{T_2}{T_1}[/tex]

Given the following data:

Access time = [tex]T_1 < T_2[/tex]

What is cache?

Cache can be defined as a random access memory (RAM) that is used by the central processing unit (CPU) of a computer system to minimize (reduce) the average time taken to access memory (AMAT).

For any single memory access, the theoretical speedup that would be used by the processor to access a word stored in the cache rather than in main memory is given by:

[tex]Speedup=\frac{T_2}{T_1}[/tex]

Where:

  • [tex]T_2[/tex] is the time to access in main memory.
  • [tex]T_1[/tex] is the time to access in cache.

Read more on processor here: https://brainly.com/question/5430107

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