Question 1
Focus on the triangle on the left.
sine is the ratio of opposite over hypotenuse
sin(angle) = opposite/hypotenuse
sin(44) = w/30
w = 30*sin(44)
w = 20.839751 approximately
Now move onto the triangle on the right. We'll use cosine this time.
cos(angle) = adjacent/hypotenuse
cos(x) = w/45
cos(x) = 20.839751/45
cos(x) = 0.463106
x = arccos(0.463106) ... arccosine is the same as [tex]\cos^{-1}[/tex]
x = 62.412286
Answers:
w = 20.839751 approximately
x = 62.412286 approximately
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Question 2
Focus on the triangle on the left.
sin(angle) = opposite/hypotenuse
sin(32) = w/5
w = 5*sin(32)
w = 2.649596
Now move to the triangle on the right.
sin(angle) = opposite/hypotenuse
sin(x) = w/5
sin(x) = 2.649596/5
sin(x) = 0.5299192
x = arcsin(0.5299192) .... arcsine is the same as [tex]\sin^{-1}[/tex]
x = 31.999996
Answers:
w = 2.649596 approximately
x = 31.999996 approximately
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Question 3
This time we use the tangent ratio.
Focus on the triangle that has legs of w and 16.
tan(angle) = opposite/adjacent
tan(70) = 16/w
w*tan(70) = 16
w = 16/tan(70)
w = 5.823524
Now let y = x+w and focus on the largest triangle this time.
tan(angle) = opposite/adjacent
tan(41) = 16/y
y = 16/tan(41)
y = 18.405895
This leads to:
y = x+w
x = y-w
x = 18.405895 - 5.823524
x = 12.582371
Answers:
w = 5.823524 approximately
x = 12.582371 approximately
