A cyclist travels a distance of 837 1/2 feet in 25 seconds. The cyclist travels at a constant rate. What is the unit rate, in feet per second, at which the cyclist travels?


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Answer:

[tex]\boxed{33.5 \ \text{feet/second}}[/tex]

Step-by-step explanation:

To find the unit rate, we need to find out how much distance does the cyclist travel in 1 second. For that, we need to use the unitary method. A unitary method is a method that determines the unit rate of an object.

Note: Since the cyclist travels at a constant rate, unitary method can be used.

[tex]\rightarrow 837 \dfrac{1}{2} \ \text{feet in 25 seconds}[/tex]

[tex]\rightarrow 837.5 \ \text{feet} = 25 \ \text{seconds}[/tex]

Divide both sides by 25:

[tex]\rightarrow \dfrac{837.5}{25} \ \text{feet} = \dfrac{25}{25} \ \text{seconds}[/tex]

[tex]\rightarrow 33.5 \ \text{feet} = 1 \ \text{seconds}[/tex]

[tex]\rightarrow \boxed{33.5 \ \text{feet/second}}[/tex]

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