The value of the quantity after 1 year, to the nearest hundredth is 4000.00
The exponential form of an equation
The standard exponential equation is eexpressed as:
[tex]P(t)=P_0e^{kt}[/tex]
Given the following parameters
[tex]P_0=4000\\r =0.0005\\t = \frac{1}{50} =0.02 (yearly)[/tex]
Substitute into the formula to have:
[tex]P(t)=4000e^{0.0005(0.02)}\\P(1)=4000e^{0.00001}\\P(1)=4000[/tex]
Hence the value of the quantity after 1 year, to the nearest hundredth is 4000.00
Learn more on exponential equations here: https://brainly.com/question/12940982
