Answer:
Step-by-step explanation:
The general formula for a horizontal hyperbola :
[tex]\frac{x^{2} }{a^{2} } -\frac{y^{2} }{b^{2} } =1[/tex]
Given: a = 1 we know a² = 1 ,and that c = 9 so we know c² = 9² = 81
We also know that the relation between a, b, c for a hyperbola is c²= a²+b²
c²= a²+b², substitute what we know
81 = 1 +b², subtract 1 from both sides of the equation
80 = b²
The equation of our hyperbola is:
[tex]\frac{x^{2} }{1 } -\frac{y^{2} }{80 } =1[/tex] or [tex]x^{2} -\frac{y^{2} }{80} =1[/tex]
