Respuesta :

fieryanswererft

Answer:

1 solution

  • x = -6

Explanation:

[tex]\rightarrow \sf y=x^2+12x+36[/tex]

[tex]\rightarrow \sf x^2+12x+36=0[/tex]

[tex]\rightarrow \sf x^2+6x+6x+36=0[/tex]

[tex]\rightarrow \sf x(x+6)+6(x+6)=0[/tex]

[tex]\rightarrow \sf (x+6)(x+6)=0[/tex]

[tex]\rightarrow \sf x=-6[/tex]

Hence there is only one solution for this quadratic equation and the value is -6

[tex]\\ \rm\rightarrowtail x^2+12x+36=0[/tex]

[tex]\\ \rm\rightarrowtail x^2+6x+6x+36=0[/tex]

[tex]\\ \rm\rightarrowtail (x+6)(x+6)=0[/tex]

Only one solution present

x=-6

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