The perimeter of the triangle ABC is [tex]10+\sqrt{10}[/tex] [tex]units[/tex].
The given parameters:
- Triangle ABC = Isosceles triangle
The length of AC = 3-(-2) = 5 unit
The length of AC = length of BC = 5 unit
The length of BC is calculated by applying Pythagoras theorem as follows;
[tex]BC^2=(4-1)^2+(3-2)^2[/tex]
[tex]BC^2=3^2+1^2[/tex]
[tex]BC^2=10[/tex]
[tex]BC=\sqrt{10}[/tex]
The perimeter of the triangle ABC is calculated as follows;
[tex]P=AB+AC+BC[/tex]
[tex]P=5+5+\sqrt{10}[/tex]
[tex]P=10+\sqrt{10[/tex] [tex]units[/tex]
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