Answer:
[tex] \large {\boxed{ \sf{y = 2x + 5}}}[/tex]
Step-by-step explanation:
Suppose the slope of the line is k.
So,
[tex] \large {\bold {k = \frac{7 - ( - 1)}{1 - (3)} = \frac{7 + 1}{1 + 3} = \frac{8}{4} = 2 }}\\ [/tex]
So the line:
[tex] \large \bold{ \frac{y - 7}{x - 1} = k = 2 } \\ [/tex]
[tex] \: [/tex]
So,
[tex] \large \bold{y - 7 = 2(x - 1)}[/tex]
[tex]\large \bold{y - 7 = 2x - 2}[/tex]
[tex]\large \bold{y = 2x - 2 + 7}[/tex]
[tex]\large \bold{y = 2x + 5}[/tex]
[tex]{\rule{200pt}{4pt}}[/tex]
[tex] \large \bold{-N} \frak{unx-}[/tex]
