The potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)
How to determine the potential zeros of the function f(x)?
The function is given as:
f(x)=6x^4+ 2x^3 - 4x^2 +2
For a function P(x) such that
P(x) = ax^n +...... + b
The rational roots of the function p(x) are
Rational roots = ± Possible factors of b/Possible factors of a
In the function f(x), we have:
a = 6
b = 2
The factors of 6 and 2 are
a = 1, 2, 3 and 6
b = 1 and 2
So, we have:
Rational roots = ±(1, 2)/(1, 2, 3, 6)
Split the expression
Rational roots = ±1/(1, 2, 3, 6)/ and ±2/(1, 2, 3, 6)
Evaluate the quotient
Rational roots = ±(1, 1/2, 1/3, 1/6, 2, 1, 2/3, 1/3)
Remove the repetition
Rational roots = ±(1, 1/2, 1/3, 1/6, 2, 2/3)
Hence, the potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)
The complete parameters are:
The function is given as:
f(x) = 3x^3 + 2x^2 + 3x + 6
The potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)
Read more about rational roots at
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