Respuesta :
The inductance of the inductor is 35.8 mH.
What is inductance?
Inductance, which would be defined as the proportion of voltage to current change rate, is what distinguishes an inductor from other electrical devices. The magnetic field induced on the coil causes inductance. The coil's form is one of the many elements that affect it.
Calculation:
Provided that,
voltage = 120 V
frequency = 1000Hz
capacitor (C) = 2.00μF
current = 0.680 A
We have to find out the inductance of that inductor by using the formula of the current,
I = V/Z
Z = [tex]\sqrt{R^{2} +(Lw - \frac{1}{Cw)^{2} } }[/tex]
Now putting the value of Z into this equation we get:
I = [tex]\frac{V}{\sqrt{R^{2}+(Lw - \frac{1}{Cw})^{2} } }[/tex]
0.680 = [tex]\frac{120}{\sqrt{100^{2}+(L* 2\pi *1000 - \frac{1}{2*10^{-6}*2\pi *1000 })^{2} } }[/tex]
L = 35.8 mH
Therefore it is concluded that the inductance of the inductor is 35.8 mH.
Learn more about inductance here:
https://brainly.com/question/15576393
#SPJ4
