In a titration experiment, 31. 4 ml of 1. 120 M HCOOH is neutralized by 16. 3 ml of [tex]Ba(OH)_{2}[/tex]. So, the concentration of the [tex]Ba(OH)_{2}[/tex] solution is 23.16 M
Calculation,
The formula for the dilution of a solution is given as:
[tex]M_{1} V_{1}[/tex] = [tex]M_{2} V_{2}[/tex]
Where M is molarity and V is the volume of the solution in liters ( L ).
Given data,
[tex]M_{1}[/tex] = 120 M
[tex]V_{1}[/tex] =31. 4 ml
[tex]M_{2}[/tex] = ?
[tex]V_{2}[/tex] = 16. 3 ml
120 M ×31. 4 ml = [tex]M_{2}[/tex] × 16. 3 ml
[tex]M_{2}[/tex] = 120 M ×31. 4 ml / 16. 3 ml =23.16 M
In a titration experiment, the concentration of the [tex]Ba(OH)_{2}[/tex] solution is 23.16 M
to learn more about dilution
brainly.com/question/13949222
#SPJ4
