Using the knowledge in computational language in JAVA it is possible to write a code that enter a series of 10 integers and then determines and displays the largest and smallest values entered.
Writting the code in JAVA:
public class OddEvenSum { // Save as "OddEvenSum.java"
public static void main(String[] args) {
// Declare variables
final int LOWERBOUND = 1;
final int UPPERBOUND = 1000; // Define the bounds
int sumOdd = 0; // For accumulating odd numbers, init to 0
int sumEven = 0; // For accumulating even numbers, init to 0
int absDiff; // Absolute difference between the two sums
// Use a while loop to accumulate the sums from LOWERBOUND to UPPERBOUND
int number = LOWERBOUND; // loop init
while (number <= UPPERBOUND) { // loop test
// number = LOWERBOUND, LOWERBOUND+1, LOWERBOUND+1, ..., UPPERBOUND
// A if-then-else decision
if (number % 2 == 0) { // Even number
sumEven += number; // Same as sumEven = sumEven + number
} else { // Odd number
sumOdd += number; // Same as sumOdd = sumOdd + number
}
++number; // loop update for next number
}
// Another if-then-else Decision
if (sumOdd > sumEven) {
absDiff = sumOdd - sumEven;
} else {
absDiff = sumEven - sumOdd;
}
// OR using one liner conditional expression
//absDiff = (sumOdd > sumEven) ? sumOdd - sumEven : sumEven - sumOdd;
// Print the results
System.out.println("The sum of odd numbers from " + LOWERBOUND + " to " + UPPERBOUND + " is: " + sumOdd);
System.out.println("The sum of even numbers from " + LOWERBOUND + " to " + UPPERBOUND + " is: " + sumEven);
System.out.println("The absolute difference between the two sums is: " + absDiff);
}
}
See more about JAVA at brainly.com/question/12975450
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