Respuesta :

Answer:

The intervals represent the domain, or the values on the horizontal axis.

When x ≤ -3, the graph should form a straight line at y = 3. Because the interval includes x = -3, the rightmost part of the line should be capped with a closed dot. The line should continue for infinity to the left.

When -3 < x < 4, the graph should form a line with the equation (2x + 1). Because the interval does not include the endpoints, the endpoints should have open dots.

When x ≥ 4, the graph should form a straight line at y = -4. Because the interval includes x = 4, the leftmost endpoint should be a closed dot. The right of the line should continue for infinity.

**The included graph does not take the endpoints into account

Ver imagen CrystalQueen

Answer:

See attached for graph.

Step-by-step explanation:

Piecewise functions have multiple pieces of curves/lines where each piece corresponds to its definition over an interval.

Given piecewise function:

[tex]f(x)=\begin{cases}3 & \textsf{if }x\leq -3\\2x+1 & \textsf{if }-3 < x < 4 \\ -2 & \textsf{if } x\geq 4 \end{cases}[/tex]

Therefore, the function has three definitions:

[tex]f(x)=3 \quad \textsf{when x is less than or equal to 3}[/tex]

[tex]f(x)=2x+1 \quad \textsf{when x is more than -3 and less than 4}[/tex]

[tex]f(x)=-2 \quad \textsf{when x is more than or equal to 4}[/tex]

When graphing piecewise functions:

  • Use an open circle where the value of x is not included in the interval.
  • Use a closed circle where the value of x is included in the interval.
  • Use an arrow to show that the function continues indefinitely.

First piece of function

Substitute the endpoint of the interval into the corresponding function:

[tex]\implies f(-3)=3 \implies (-3,3)[/tex]

Place a closed circle at (-3, 3).

As this piece of the function is f(x) = 3 for any value of x that is less than or equal to -3, draw a horizontal straight line to the left from the closed circle.  Add an arrow at the end.

Second piece of function

Substitute the endpoints of the interval into the corresponding function:

[tex]\implies f(-3)=2(-3)+1=-5 \implies (-3,-5)[/tex]

[tex]\implies f(4)=2(4)+1=9 \implies (4,9)[/tex]

Place an open circle at (-3, -5) and (4, 9).

Join the points with a straight line.

Third piece of function

Substitute the endpoint of the interval into the corresponding function:

[tex]\implies f(4)=-2 \implies (4,-2)[/tex]

Place a closed circle at (4, -2).

As this piece of the function is f(x) = -2 for any value of x that is more than or equal to 4, draw a horizontal straight line to the right from the closed circle.  Add an arrow at the end.

Learn more about piecewise functions here:

https://brainly.com/question/28151925

https://brainly.com/question/11562909

Ver imagen semsee45