All the equation is false and discuss below. They are the algebraic equation.
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Though it looks like the following equations are true, each of them actually false. Confirm this by substituting simple numbers for the variables and doing the arithmetic. Note: Do not use 0 or 1; they are too special. A. (x+y)2=x2+y2 B. √(p^2+q^2 ) = p + q C. 3w-2 = 1/3w2 D. (a-1 + b-1)-1 = a+b E. 3.2x = 6x
A. Assume x=2 , y=3 so, (x+y)² = 25 and x²+y² = 13. So, the algebraic equation is false.
B. Assume p=3, q=4 so, √(p²+q2 ) = 5 and p+q= 7. So, the algebraic equation is false.
C. Assume, w= 3 so, 3w⁻² = 1/3 and 1/3w²= 1/27. So, the equation is false.
D. Assume, a=2, b=3 so, (a⁻¹ + b⁻¹)⁻¹ = 6/5 and a+b= 5. So, the equation is false.
E. Assume, x= 2 so, 3·2ˣ = 12 and 6x = 36. So, the equation is false.
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