When the length of the pendulum in pendulum clock increases by 0.1 % , then the error in time per day is c) 43.2s
Let the pendulum = L
The time in a day will be: = 60 × 60 × 24
When the length is increased, the new length will be:
= L + 0.001L
New time period will be:
T =✓0.001s
Now, the error in a day will be:
= ✓0.001 × 60 × 60 × 24 - 1 × 60 × 60 × 24.
= 60 × 60 × 24(✓1.001 - 1)
= 43.2 seconds.
Therefore, the correct option is C.
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