Given:
• Initial amount in the checking account = $638.54
,• Amount of balance she must maintain = $500
,• Amount of check she wrote = $159.50
Let's write and solve an inequality that would be used for the least amount of money she needs to deposit to avoid a fee.
Since she wrote a check of $159.50, the balance in the account will be:
$638.54 - $159.50
Now, for the inequality which will show the least amount to be deposited to avoid a fee, we have:
638.54 - 159.50 + x ≥ 500
Where x represents the amount of money that is to be deposited.
Now, let's solve the inequality for x.
479.04 + x ≥ 500
Subtract 479.04 from both sides:
479.04 - 479.04 + x ≥ 500 - 479.04
x ≥ 20.96
The least amount that should be deposited to avoid a fee is $20.96
Therefore, the inequality is:
[tex]638.54-159.50+x\ge500[/tex]ANSWER:
[tex]638.54-159.50+x\ge500[/tex]
