ANSWER:
[tex](1,1)\text{ and }(-3,9)[/tex]STEP-BY-STEP EXPLANATION:
Graphically the solution are points of intersection between both graphs, just like this:
We have the following system of equations:
[tex]\begin{gathered} y=x^2 \\ y=-2x+3 \end{gathered}[/tex]We solve by means of equalization
[tex]\begin{gathered} x^2=-2x+3 \\ x+2x-3=0 \\ (x-1)(x+3)=0 \\ x-1=0\rightarrow x=1 \\ x+3=0\rightarrow x=-3 \end{gathered}[/tex]Now, for y:
[tex]\begin{gathered} y=1^2=1 \\ y=(-3)^2=9 \end{gathered}[/tex]Therefore, the solutions are:
[tex](1,1)\text{ and }(-3,9)[/tex]
