1) Moles of NaCl in 200.0 mL of solution.
[tex]\text{Molarity (M)=}\frac{\text{moles of solute}}{\text{liters of solution}}[/tex]Solve for moles
[tex]\text{moles of solute=Molarity}\cdot\text{liters of solution}[/tex]Convert mL into L.
[tex]L=200.0mL\cdot\frac{1L}{1000mL}=0.200L[/tex]Plug in know values
[tex]\text{moles of NaCl=1.00 M}\cdot0.200L=0.20molNaCl_{}[/tex]There are 0.20 moles of NaCl in 200.0 mL of solution.
2) grams of NaCl in 200.0 mL of solution.
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