Respuesta :
Answer:
0.284L
Explanations
The balanced chemical reaction between sodium and water is expressed as:
[tex]2Na(s)+2H_2O(l)\rightarrow2NaOH(aq)+H_2(g)[/tex]Determine the moles of sodium Na that reacted
[tex]\begin{gathered} moles\text{ of Na}=\frac{mass}{molar\text{ mass}} \\ moles\text{ of Na}=\frac{0.52}{23} \\ moles\text{ of Na}=0.0226moles \end{gathered}[/tex]Based on stoichiometry, 2moles of sodium produces 1 mole of hydrogen gas. The moles of hydrogen gas required is given as:
[tex]\begin{gathered} mole\text{ of H}_2=\frac{1}{2}\times0.0226 \\ mole\text{ of H}_2=0.0113moles \end{gathered}[/tex]According to the ideal gas equation
[tex]\begin{gathered} PV=nRT \\ V=\frac{nRT}{P} \end{gathered}[/tex]Given the following
P = 740mmHg = 0.974atm
T = 25 +273 = 298K
R = 0.08205 Latm/molK (Gas constant)
Substitute the given parameters into the formula to have:
[tex]\begin{gathered} V=\frac{0.0113\times0.08205\times298}{0.974} \\ V=\frac{0.2764}{0.974} \\ V=0.284L \end{gathered}[/tex]Hence the volume of hydrogen gas that evolved from the reaction is 0.284L
