Solve the following system of equations by using elimination:
[tex]\begin{cases}x+2y=8\ldots\ldots\text{.}(1) \\ -x-3y=2\ldots\ldots(11)\end{cases}[/tex]
Using Elimination method:
[tex]\begin{gathered} \begin{cases}x+2y=8 \\ \frac{-x-3y=2}{-y=10}\end{cases}\text{+} \\ \text{divide both side by -1} \\ -\frac{y}{-1}=\frac{10}{-1} \\ y=-10 \end{gathered}[/tex]
Substitute the value of y in equation (1):
[tex]\begin{gathered} x_{}+2y=8 \\ x+2(-10)=8 \\ x-20=8 \\ x=8+20 \\ x=28 \end{gathered}[/tex]
Therefore the value of x = 28 and y = -10
Hence the correct answer is (x,y) = (28,-10)
