From the given equation y=16, it implies that the line has no slope.
Hence, the slope is zero (0).
From the given point:
[tex]\begin{gathered} (-7,43) \\ x_1=-7,y_1=43 \end{gathered}[/tex]The equation of the line is given by the equation:
[tex]m=\frac{y-y_1}{x-x_1}[/tex][tex]\begin{gathered} 0=\frac{y-43}{x-(-7)} \\ 0=\frac{y-43}{x+7} \\ \text{cross}-\text{multiply} \\ y-43=0 \\ y=43 \end{gathered}[/tex]Hence, the equation of the line is y=43
