The force acting on the car can be expressed as,
[tex]F=ma[/tex]Plug in the known values,
[tex]\begin{gathered} 3000\text{ N=(1400 kg)a} \\ a=\frac{3000\text{ N}}{1400\text{ kg}}(\frac{1kgm/s^2}{1\text{ N}}) \\ =2.14m/s^2 \end{gathered}[/tex]Thus, the acceleration of the car is 2.14 m/s2.
The final velocity of the car is given as,
[tex]v=u+at[/tex]Substitute the known values,
[tex]\begin{gathered} v=0m/s+(2.14m/s^2)(10\text{ s)} \\ =21.4\text{ m/s} \end{gathered}[/tex]Thus, the final velocity of the car is 21.4 m/s.
