I'll start first by finding the slope of the line at t = 2 mins up to t = 6 mins, t = 6 mins up to t = 8 mins, and t = 14 mins up to t = 20 mins.
For the first interval (2 mins to 6 mins), we have the coordinates (2, 7) and (6, 5). The slope of the line is
[tex]m=\frac{5-7}{6-2}=-\frac{2}{4}=-\frac{1}{2}[/tex]For the second interval (6 mins up to 8 mins), we have the coordinates (6, 5) and (8,0). The slope of the line is
[tex]m=\frac{0-5}{8-6}=-\frac{5}{2}[/tex]For the last interval (14 mins up to 20 mins), we have the coordinates (14,0) and (20,9). The slope of the line is
[tex]m=\frac{9-0}{20-14}=\frac{9}{6}[/tex]The x-axis of the given graph pertains to time while its y-axis pertains to distance from home. Let's try to make a story about a person from work going home and will prepare something before going outside again.
For the first 2 mins, the person walks out of his office and will go to his car. Since he is still in the office, the distance from home does not change for the first two minutes.
For the next 4 mins (2 mins to 6 mins interval), he starts driving going home at a rate of 1/2 miles per minute. Because of traffic, he is driving slower than his usual driving speed. Upon passing away from the traffic, the person now travels at a rate of 5/2 miles per minute for 2 mins (6 to 8 mins interval). At the 8th minute mark, he is already home. He prepared something at home during the 8 min to 14 min interval time. After the preparation, he went again outside for some business trip, traveling at the speed of 9/6 miles per minute.
