Respuesta :

Given:

Geometric sequence:

[tex]\frac{3}{2},\frac{3}{4},\frac{3}{8},.....[/tex]

Find-: Next term of the geometric.

Sol:

Common ratio of a geometric sequence.

[tex]r=\frac{a_n}{a_{n-1}}[/tex]

A common ratio is:

[tex]\begin{gathered} r=\frac{\frac{3}{4}}{\frac{3}{2}} \\ r=\frac{3}{4}\times\frac{2}{3} \\ r=\frac{1}{2} \end{gathered}[/tex]

The next term is:

[tex]a_n=ra_{n-1}[/tex][tex]\begin{gathered} =\frac{1}{2}\times\frac{3}{8} \\ =\frac{3}{16} \end{gathered}[/tex]