For the following set of data, find the percentage of data within population standarddeviations of the mean, to the nearest percent.88, 92, 57, 62, 57, 56, 58, 57Copy Values for CalculatorOpen Statistics Calculator

For the following set of data find the percentage of data within population standarddeviations of the mean to the nearest percent88 92 57 62 57 56 58 57Copy Val class=

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Answer: 100 %

Explanation:

The first step is to rearrange the numbes in ascending order. It becomes

56, 57, 57, 57, 58, 62, 88, 92

The next step is to calculate the population μ, mean.

μ = sum of terms/number of terms

From the information given

n = number of terms = 8

μ = (56 + 57 + 57 + 57 + 58 + 62 + 88 + 92)/8 = 65.875

μ = 65.875

The formula for calculating the population standard deviation, σ is

σ = √[Σ(x - μ)^2]/n

Σ(x - μ)^2/n = [(56 - 65.875)^2 + (57 - 65.875)^2 + (57 - 65.875)^2 + (57 - 65.875)^2 + (58 - 65.875)^2 + (62 - 65.875)^2 + (88 - 65.875)^2 + (92 - 65.875)^2)]/8 = 197.859375

σ = √197.859375

σ = 14.1

2 population standard deviations to the left of the mean = 65.875 - 2(14.1) = 37.675

2 population standard deviations to the rig tof the mean = 685875 -+2(14.1) == 94.075

Number of terms between 37.675 and 94.075 = 8

Thus,

the percentage of data within 2 population standard deviations of the mean

= 8/8 x 100 = 100%