1.875M is the molarity of an HCl solution if it takes 25.00 ml of a 0.750 m NaOH solution to neutralize 10.00 ml of the HCl solution
The Balanced reaction for the equation is given by:
HCl+NaOH⇌H₂O+NaCl
It is given that the molarity of NaOH is 0.750M, the volume of HCl is 25ml, the volume of HCl to be neutralized is 10ml.
Then,
By titration:
We know that,
Molarity = n/V
n = Molarity x V
0.025 L of 0.750 mol/L of NaOH= No of moles of NaOH
No of moles NaOH = 0.025 x 0.750
No of moles of NaOH = 0.01875 mol
Then it can be written that,
0.01875 mol NaOH ⋅ 1 mol HCl/1 mol NaOH =
0.01875 mol HCl
Now,
0.01875 mol HCl / 0.010 L =1.875M HCl
Therefore, the molarity is 1.875M
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