2.19 litres of oxygen at 350 °C and at 5.25 atm are needed to convert 5.00 g of S to SO₃.
Using the equation- S + 3/2 O₂ → SO₃
Moles of sulfur- 5/32 = 0.15 mol
Given the stoichiometry, we require [tex]\frac{3}{2} * 0.15\\[/tex] mol of dioxygen gas. = 0.225 mol.
And now we solve for volume in the Ideal Gas equation:
V = nRT /P
V= 0.225 mol x 0.0821L atm K⁻¹ x 623 K / 5.25
V= 2.19 L
Hence, 2.19 Liters of oxygen at 350 °C and at 5.25 atm are needed to convert 5.00 g of S to SO₃.
To learn more about Ideal gas equation refer- https://brainly.com/question/24236411
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