calculate the volume in ml of 0.50 m sodium hydroxide that is needed to neutralize 1.8000 g of potassium hydrogen phthalate (khp). (molar mass of potassium hydrogen phthalate (khp)

Respuesta :

Neutralization is a chemical reaction in which acid and a base react quantitatively with each other. The product obtained here is salt and water. It is even called as a double replacement reaction.

How can we calculate volume after neutralization process?

KHC8H4O4 is potassium hydrogen phthalate (KHP).

The balanced equation for the reaction:

KHC8H4O4 + NaOH ==> KNaC8H4O4 + HOH

So, the stoichiometry is 1 moles NaOH needed for 1 mole of KHP.

Molar mass of KHP = 204 g/mol

Thus, volume after neutralization process is

= 1.800 g KHP x 1 mole KHP/204 g

= 0.00882 moles

It will take 0.00882 moles of NaOH to neutralize this.

To know more about neutralization, click on https://brainly.com/question/23008798

#SPJ4