One mole or 239.2 g of PbO₂ or 239.2 g gives two moles or 606.5 of lead sulphate. Thus, 23.6 g of lead oxide will give 59.84 g of lead sulphate.
Lead oxide is an ionic compound formed by the ionic bonding between the transition metal lead and oxygen by losing two electrons from lead to oxygen. It reacts with sulphuric acid giving lead sulphate PbSO₄.
As per the given balanced reaction, one mole of lead oxide gives two moles of lead sulphate.
Molar mass of PbO₂ = 239.2 g/mol
Molar mass of PbSO₄ = 303.27 g/mol
2 moles of PbSO₄ = 2 × 303.27 = 606.54 g.
Thus, 239.2 g of lead oxide gives 606.54 g of PbSO₄. The mass of PbSO₄ produced from 23.6 g of lead oxide is:
= (23.6 × 606 .54 )/ 239.2 g
= 59.84 g.
Therefore, the mass of PbSO₄ produced from 23.6 g of PbO2 is 59.84 g.
To find more on lead oxide, refer here:
https://brainly.com/question/13264277
#SPJ1
