The grams of SO₃ are produced when 20.0 g FeS₂ reacts with 16.0 g O₂ is 26.56 grams.
How we calculate mass from moles?
Mass from moles of any substance will be calculated as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction is:
4FeS₂(s) + 15O₂(g) → 2Fe₂O₃ + 8SO₃(g)
Moles of 20g FeS₂ = 20g / 119.98g/mol = 0.166 mole
Moles of 16g of O₂ = 16g / 16g/mol = 1 mole
From the moles of reactant it is clear that FeS₂ is the limitng reagent and formation of SO₃ also depends on this.
From the stoichiometry of the reaction, it is clear that:
4 moles of FeS₂ = produce 8 moles of SO₃
0.166 moles of FeS₂ = produce 8/4×0.166=0.332 moles of SO₃
Now we calculate the mass of SO₃ as:
W = 0.332mol × 80g/mol = 26.56 grams
Hence, mass of SO₃ is 26.56 grams.
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https://brainly.com/question/24322641
