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a surveyor measures the angle of elevation to a point on a mountain to be 18 degrees. the point on the mountain is horizontally 4 miles away from the surveyor.the vertical change in elevation from the point where the surveyor is standing to the point on the mountain is

Respuesta :

The answer is 1.3 (This is rounded to the nearest hundredth.)


Answer:

Using tangent ratio:

[tex]\tan \theta = \frac{\text{opposite side}}{\text{Adjacent side}}[/tex]

As per the statement:

A surveyor measures the angle of elevation to a point on a mountain to be 18 degree.

Angle of elevation [tex](\theta)[/tex] = 18 degree.

It is also given that:

the point on the mountain is horizontally 4 miles away from the surveyor.

Let y be the vertical change in elevation from the point where the surveyor is standing to the point on the mountain.

See the diagram as shown below in the attachment

we have;

Opposite side = y miles and adjacent side = 4 miles

Using tangent ratio:

[tex]\tan 18^{\circ} = \frac{y}{4}[/tex]

then;

[tex]0.3249196 = \frac{y}{4}[/tex]

Multiply both sides by 4 we have;

[tex]1.2996 = y[/tex]

or

[tex]y \approx 1.3[/tex] miles.

Therefore, 1.3 miles is the the vertical change in elevation from the point where the surveyor is standing to the point on the mountain

Ver imagen OrethaWilkison