Answer:
The correct answer is option A.
Explanation:
Pressure of the gas ,P= 0.9 kPa = 0.008882 atm
1 kPa = 0.0098 atm
Number of moles gases = n = 0.04 mol
Temperature of the gas ,T =20°C = 293 K
Volume of the gas = V
Using An Ideal gas equation:
PV=nRT
[tex]V=\frac{nRT}{P}=\frac{0.04 mol\times 0.0820 atm L/mol K\times 293 K}{0.008882 atm}=108.20 L\approx 108 L[/tex]
Hence, the correct answer is option A.
