How many moles of nitrogen, N, are in 82.0 g of nitrous oxide, N2O?

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vanhkhuyentt2 vanhkhuyentt2 · Answer 1 · 2017-04-03T17:17:49+02:00

moles of N20 is: 82/(14*2+16)= 1.86 (moles)
In N2O there are 2 nitrogen so moles of nitrogen will be: 1.86 * 2 = 3.72 (moles)

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Alleei Alleei · Answer 2 · 2019-10-05T13:22:20+02:00

Answer : The number of moles of nitrogen present in nitrous oxide are 3.72 moles.

Explanation : Given,

Mass of = 82.0 g

Molar mass of [tex]N_2O[/tex] = 44 g/mole

First we have to calculate the moles of [tex]N_2O[/tex].

[tex]\text{ Moles of }N_2O=\frac{\text{ Mass of }N_2O}{\text{ Molar mass of }N_2O}=\frac{82.0g}{44g/mole}=1.86moles[/tex]

Now we have to calculate the moles of nitrogen in nitrous oxide.

In nitrous oxide [tex]N_2O[/tex], there are 2 moles of nitrogen and 1 mole of oxygen.

As, 1 moles of [tex]N_2O[/tex] contains 2 moles of nitrogen

So, 1.86 moles of [tex]N_2O[/tex] contains [tex]1.86\times 2=3.72moles[/tex] of nitrogen

Therefore, the number of moles of nitrogen present in nitrous oxide are 3.72 moles.