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Suppose a binomial event has a probability of success of 0.3, and 1250 trials are performed. What is the standard deviation of the possible outcomes? Round your answer to two decimal places.

Respuesta :

LammettHash
[tex]\sqrt{1250\times0.3\times(1-0.3)}\approx16.20[/tex]
JeanaShupp

Answer: 16.20

Step-by-step explanation:

For any binomial event , the formula to calculate the standard deviation of the possible outcomes is given by :-

[tex]\sigma=\sqrt{\text{p(1-p)n}}[/tex]

Given: The probability of success p = 0.3

Then , the probability of failure q= 1-0.3=0.7

Now,  by using above formula , the standard deviation of the possible outcomes will be :-

[tex]\sigma=\sqrt{0.3\times0.7\times1250}\\\\\Rightarrow\sigma=\sqrt{262.5}\\\\\Rightarrrow\sigma=16.201851746\approx16.20[/tex]

Hence, the standard deviation of the possible outcomes = 16.20

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