Solving for Angles
[tex]\displaystyle \frac{sin∠C}{c} = \frac{sin∠B}{b} = \frac{sin∠A}{a}[/tex]
Make sure to use [tex]\displaystyle sin^{-1}[/tex]towards the end, or elce you will throw your answer off!
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Solving for Edges
[tex]\displaystyle \frac{c}{sin∠C} = \frac{b}{sin∠B} = \frac{a}{sin∠A}[/tex]
I am joyous to assist you at any time.
