Answer : The amount of heat produced during the combustion of hexane per mole is 4109.79 kJ/mole.
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
Formula used :
[tex]Q=m\times c\times \Delta T[/tex]
where,
Q = heat absorb = ?
m = mass of calorimeter = 1.900 kg = 1900 g
c = specific heat of calorimeter = [tex]3.21J/g.K[/tex]
[tex]\Delta T[/tex] = change in temperature = 4.542 K
Now put all the given value in the above formula, we get:
[tex]Q=1900g\times 3.21J/g.K\times 4.542K[/tex]
[tex]Q=27701.658J=27.70kJ[/tex]
Now we have to calculate the moles of hexane.
[tex]\text{Moles of }C_6H_{14}=\frac{Mass of }C_6H_{14}}{Molar mass of }C_6H_{14}=\frac{0.580g}{86.18g/mole}=0.00674mole[/tex]
Now we have to calculate the heat produced during the combustion of hexane per mole.
[tex]\text{Heat produced}=\frac{27.70kJ}{0.00674mole}=4109.79kJ/mole[/tex]
Therefore, the amount of heat produced during the combustion of hexane per mole is 4109.79 kJ/mole.
