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Find the factors and zeros of 6x2 + 8x - 28 = 2x2 + 4?
A) 2(x + 4)(x + 2); {-4, -2}
B) 4(x + 4)(x - 2); {-4, 2}
C) 4(x - 4)(x + 2); {4, -2}
D) 4(x - 4)(x - 2); {4, 2}

Respuesta :

Edufirst
First solve the equation:


6x^2 + 8x  -28 = 2x^2 + 4

=> 6x^2 - 2x^2 + 8x - 28 - 4 = 0

=> 4x^2  + 8x - 32 = 0


Extract common factor 4:


=> 4[x^2 + 2x - 8] = 0


Now factor the polynomial:


4(x + 4) (x - 2) = 0


=> the solutions are x + 4 = 0 => x = -4, and x - 2 = 0 => x = 2.


So the answer is the option B: 4(x + 4)(x - 2); {-4, 2} 


cowchowyt

Answer:

First solve the equation:

6x^2 + 8x  -28 = 2x^2 + 4

=> 6x^2 - 2x^2 + 8x - 28 - 4 = 0

=> 4x^2  + 8x - 32 = 0

Extract common factor 4:

=> 4[x^2 + 2x - 8] = 0

Now factor the polynomial:

4(x + 4) (x - 2) = 0

=> the solutions are x + 4 = 0 => x = -4, and x - 2 = 0 => x = 2.

So the answer is the option B: 4(x + 4)(x - 2); {-4, 2} 

Read more on Brainly.com - https://brainly.com/question/3949307#readmore

Step-by-step explanation:

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