Respuesta :

JKM = M + L
15x - 48 = 40 + 5x + 12
10x - 48 = 52
10x = 100
x = 10
JKM = 15(10) - 48 = 102

180 = JKM + MKL
180 = 102 + MKL
MKL = 180 - 102 = 78

The required angle MKL = 96⁰

What are the angle sum property of a triangle?

In a Euclidean space, the sum of angles of a triangle equals the straight angle. A triangle has three angles, one at each vortex, bounded by a pair of adjacent sides.

Mathematically,if ABC is a traingle with sides A,B and C. Then,

                    ∠A  + ∠B  +  ∠C  = 180⁰

Now,it is given that

∠JKM = 15x-48

∠L= 5x+12

∠M= 40

So, In ΔMKL,

Since sum of all the angles = 180⁰

⇒ ∠K + ∠L  + ∠M = 180⁰

⇒ ∠JKM + (5x+12)  + 40 = 180⁰

⇒ (15x-48) + (5x+12)  + 40 = 180⁰

⇒ 15x + 5x + 12 - 48 + 40 = 180⁰

⇒ 20x + 12 - 8 = 180⁰

⇒ 20x + 4 = 180⁰

⇒ 20x  = 180⁰ - 4

⇒ 20x  = 176⁰

⇒  x  = 176/20⁰

 x  = 88/10⁰

Putting the value of x in ∠JKM. We get,

    ∠ JKM = 15 (88/10) - 48

⇒   ∠JKM=  132 - 48

⇒   ∠JKM=  84

∵ Angle of straight line = 180⁰

∴Taking the straight line JKL from the figure shown. We have

       ∠JKM + ∠MKL = 180⁰

Putting the values of ∠JKM. We have

⇒     84 + ∠MKL = 180⁰

⇒     ∠MKL = 180⁰ - 84

⇒     ∠MKL =  96⁰

Hence, the required angle MKL is 96⁰.

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