Archimedes drained the water in his tub. 62.5 liters of water were drained each minute, and the tub was completely drained after 8 minutes. Graph the amount of water left in the tub (in liters) as a function of time (in minutes).

Respuesta :

Answer:

y = -7.8125x + 62.5

Step-by-step explanation:

x represents the number of minutes

y represents the amount of water left

When x=0 , y= 62.5  so its (0,62.5)

When x= 8, y=0 so its (8,0)

Now we frame equation using y=mx+b

[tex]m=\frac{y_2-y_1}{x_2-x_1} =\frac{0-62.5}{8-0} = -7.8125[/tex]

(0,62.5) is the y intercept , the value of b= 62.5

So equation becomes y = -7.8125x + 62.5

Graph is attached below

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Lanuel

The graph of the amount of water left in the tub (in liters) is a straight-line graph and it is shown in the image attached below.

How to calculate the volume of water left.

Based on the information provided, we know that 62.5 liters of water were drained from the tub per minute. Also, the tub was completely drained after 8 minutes.

The initial volume of water in the tub is given by:

Volume = 62.5 × 8

Volume = 500 liters.

Also, the volume of water left in the tub after x minutes is given by:

y = 500 - 62.5x

When x = 1, we have:

y = 500 - 62.5(1) = 437.5 liters.

When x = 2, we have:

y = 500 - 62.5(2) = 375 liters.

When x = 3, we have:

y = 500 - 62.5(3) = 312.5 liters.

When x = 4, we have:

y = 500 - 62.5(4) = 250 liters.

When x = 5, we have:

y = 500 - 62.5(5) = 187.5 liters.

When x = 6, we have:

y = 500 - 62.5(6) = 125 liters.

When x = 5, we have:

y = 500 - 62.5(7) = 62.5 liters.

When x = 8, we have:

y = 500 - 62.5(8) = 0 liters.

In conclusion, the graph of the amount of water left in the tub (in liters) is a straight-line graph because there exist a linear relationship between the volume of water and time.

Read more on graphs here: https://brainly.com/question/25875680

Ver imagen Lanuel