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Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).

Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints 4 1 and 2 5 class=

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AJ135
the gradient is 3 The y intercept is -12
The equation of the line is y=3x-12
Perpendicular bisectors have a negative gradient
y=-3x +12
MellyP
My fist step to solving this question would be to find the mid-point of the given line. 

The mid point of (4,1) and (2,-5) is (3,-2). The mid point is where the perpendicular bisector connects or bisects the given segment. 

My second step would be to graph the two given points and to connect them, forming a line. This way, I would know the slope of the line and then I would be able to find the slope of the perpendicular bisector, since the slope for perpendicular lines is the opposite reciprocal of the given line.

In doing this, I discovered that the slope of the segment with the given endpoints is 3 which means that the slope of the perpendicular bisector will be -1/3.

So, so far we've got a point of intersection and a slope which is all we need to formulate the equation of the line that we are looking for.

In the end, our answer will be y= -1/3x - 1.
Ver imagen MellyP