Answer : The hybridization of central atom in [tex]SeOF_2[/tex] is [tex]sp^3[/tex]
Explanation :
Formula used :
[tex]\text{Number of electron pair}=\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
Now we have to determine the hybridization of the given molecule.
The given molecule is, [tex]SeOF_2[/tex]
In this molecules, the central atom will be selenium not oxygen because selenium is less electronegative atom than the oxygen.
[tex]\text{Number of electrons}=\frac{1}{2}\times [6+2]=4[/tex]
The number of electron pair are 4 that means the hybridization will be [tex]sp^3[/tex] and the electronic geometry of the molecule will be tetrahedral.
But as there are 3 atoms around the central selenium atom, the fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be trigonal pyramidal.
Hence, the hybridization of central atom in [tex]SeOF_2[/tex] is [tex]sp^3[/tex]
