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An old-fashioned Chinese restaurant offers a family dinner where you get to choose one dish from “column A” (which has 8 dishes), one dish from “column B” (which has 10 dishes) and one dish from “column C” (which has 5 dishes). How many different family dinners can be chosen?

Respuesta :

jpidmeak
The answer is 10 times 8 times 5 or 400
JeanaShupp

Answer:  400

Step-by-step explanation:

Given : The number of dishes in column A = 8

The number of dishes in column B = 10

The number of dishes in column C = 5

Since for dinner we need to choose one dish from each column, then

The total number of combinations of dishes for dinner will be :-

[tex]8\times10\times5=400[/tex]

Hence, the number of family dinners =400

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