A car rental rents out SUV's for $300 a week and sedans for $220 a week. If the owner of the rental wants $75,000 in revenue, how many SUV's must be rented if 150 sedans are rented?

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Answer:

Step-by-step explanation:

Let's denote the number of SUVs rented as \( S \) and the number of sedans rented as \( 150 \) (as given).

The revenue from renting SUVs is \( $300 \) per week, and the revenue from renting sedans is \( $220 \) per week.

The total revenue (\( R \)) is the sum of the revenue from SUVs and sedans, and it should be equal to the owner's revenue target (\( $75,000 \)):

\[ R = 300S + 220 \times 150 \]

Now, we set up an equation using the revenue target:

\[ 75,000 = 300S + 220 \times 150 \]

Solve for \( S \):

\[ 75,000 = 300S + 33,000 \]

Subtract \( 33,000 \) from both sides:

\[ 42,000 = 300S \]

Divide both sides by \( 300 \):

\[ S = \frac{42,000}{300} \]

\[ S = 140 \]

Therefore, the owner needs to rent out \( 140 \) SUVs in addition to the \( 150 \) sedans to achieve a revenue of \( $75,000 \).

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Answer:

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Step-by-step explanation:

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