Answer:
5.65 kilojoules
Explanation:
To Calculate the energy released as the silver solidified, we can use Latent heat Equation. The heat consumed or released by the substance or the latent heat of fusion formula is expressed as
- [tex] {\boxed{\sf {Q = mL}}} [/tex]
Where:
- Q is Energy released
- L is specific latent heat of fusion of silver, i.e 11.3 kJ/kg
- m is mass of silver (500 g = 0.5 kg)
Substitute the required values in the above eqn,
[tex]\sf Q = 0.5 \ kg \times 11.3 \ kJ/Kg [/tex]
[tex]\sf Q \approx 5.65 \ kJ [/tex]
Hence, approximately 5.65 kilojoules of energy were released as the silver solidified.
