The length of rectangle B is 25% greater than the length of rectangle A.

The width of rectangle B is 3/5x the width of rectangle A.


Find the fraction:

Area of rectangle B ÷ Area of rectangle A

Give your answer in its simplest form.

Respuesta :

Answer:

3/4

Step-by-step explanation:

If the length of B is 25% bigger than the length of A then the size of [tex]L_B[/tex] is 1.25 that of [tex]L_A[/tex] (or 0.25[tex]L_A[/tex] added to [tex]L_A[/tex]) or 5/4[tex]L_A[/tex]

They also tell us that the width of rectangle B is 3/5 of A's so it's [tex]3/5W_A[/tex]

multiply [tex]L_A[/tex] and [tex]W_A[/tex] to get the area of rectangle B and we get 3/4[tex]L_AW_A[/tex]

already knowing from the problem that recatngle A has a length and width (which we referred to when solving for B's area) its area is [tex]L_AW_A[/tex]

dividing B's area with A's we get: (3/4)/1 or 3/4