For Part A, in creating the square, you did it correctly.
Now for Part B, you can create a right triangle by adding a point at -4, -3, and we'll call it, say, T.
Then you can use the Pythagorean's Theorem to find the length of one side of the square.
The Pythagorean's Theorem is [tex] a^{2} + b^{2} = c^{2} [/tex]
A would be the distance between P and T, and B would be the distance between Q and T. So then, a would be 7, and B would be 2.
To fill it in, it would be [tex]7^{2} + 2^{2} = c^{2} [/tex]
or 49 + 4 = [tex] c^{2} [/tex]
or 53 = [tex]c^{2} [/tex]
or [tex] \sqrt{53} [/tex] = x
Which is equal to about 7.28
Now multiply that by 4 to get the perimeter, or 29.12
So the perimeter would be about 29.12
