contestada

An astronaut on another planet drops a 1-kg rock from rest and finds that it falls a vertical distance of 2.5 meters in one second. on this planet, the rock has a weight of: (hint: use d= 1/2 g t^2 to find g; then use w = mg to find weight.)

Respuesta :

x=.5(a)t^2 can be used: 2.5m=.5(g)(1), g=5m/s^2. 

Answer:

Weight = 5 N

Explanation:

As we know that rock falls a distance of 2.5 m in one second so now we can use kinematics to find the acceleration of the rock

[tex]d = \frac{1}{2}gt^2[/tex]

here we know

d = 2.5 m

t = 1 s

now from above equation we know

[tex]2.5 = \frac{1}{2}g(1)^2[/tex]

[tex]g = 5 m/s^2[/tex]

So here the weight of the rock is given as

[tex]W = mg[/tex]

[tex]W = 1\times 5[/tex]

[tex]W = 5 N[/tex]

Otras preguntas