Suppose that you add 10 to all of the observations in a sample. how does this change the sample mean? how does it change the sample standard deviation?

Respuesta :

It just means youre adding 10 too whatever number you have.

Adding 10 to every observation in a sample, the sample mean would be 10 more the precious one and the standard deviation will remain the same.

What is mean of sample?

"It is an average of a set of data."

What is formula of mean of sample?

"For a sample of observation [tex]x_1,x_3,x_2,...,x_n[/tex] the mean of the sample is,

[tex]\Rightarrow \bar{X}=\frac{x_1+x_3+x_2+...+x_n}{n}[/tex]"

What is standard deviation?

"It is a measure of how dispersed the data from the mean."

Formula for standard deviation?

[tex]\Rightarrow \sigma=\sqrt{\frac{\Sigma(x_i-\bar{X})^2}{N}}[/tex]

where, [tex]\bar{X}[/tex] is the mean of sample and N is the size of sample

For given question,

Let [tex]x_1,x_3,x_2,...,x_n[/tex] be a sample observation.

We need to check if we add 10 to all of the observations in a sample, then does this change the sample mean. Also we have to check how does it change the sample standard deviation.

Let [tex]\bar{X}[/tex] be the mean of [tex]x_1,x_3,x_2,...,x_n[/tex]

[tex]\Rightarrow \bar{X}=\frac{x_1+x_3+x_2+...+x_n}{n}[/tex]

We add 10 to all of the observations in a sample.

[tex]\Rightarrow x_1+10,x_3+10,x_2+10,...,x_n+10[/tex]

The mean of above sample would be,

[tex]=\frac{(x_1+10)+(x_3+10)+(x_2+10)...+(x_n+10)}{n}\\\\=\frac{10n + (x_1+x_3+x_2+...+x_n)}{n}\\\\ =\frac{10n}{n} +\frac{x_1+x_3+x_2+...+x_n}{n}\\\\ =10 + \bar{X}[/tex]

This means, if we add 10 to every observation in a sample then the sample mean we 10 more the precious one.

In case of standard deviation,

adding 10 to every observation will not change the [tex](x_i-\bar{X})[/tex] factor.

This means, the standard deviation will remain the same.

Therefore, adding 10 to every observation in a sample, the sample mean would be 10 more the precious one and the standard deviation will remain the same.

Learn more about mean and standard deviation here:

https://brainly.com/question/16030790

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