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A table tennis ball with a mass of 0.003 kg and a soccer ball with a mass of 0.43 kg or both Serta name motion at 16 M/S calculate and compare the moments of both balls

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samuraijack
Let us first know the given: Tennis ball has a mass of 0.003 kg, Soccer ball has a mass of 0.43 kg. Having the same velocity at 16 m/s. First the equation for momentum is P=MV P=Momentum M=Mass V=Velocity. Now let us have the solution for the momentum of tennis ball. Pt=0.003 x 16 m/s= (    kg-m/s ) I use the subscript "t" for tennis.  Momentum of Soccer ball Ps= 0.43 x 13m/s = (      km-m/s). If we going to compare the momentum of both balls, the heavier object will surely have a greater momentum because it has a larger mass, unless otherwise  the tennis ball with a lesser mass will have a greater velocity to be equal or greater than the momentum of a soccer ball.

Answer:

Momentum of tennis ball = 0.048 [tex]\frac{kg m}{s}[/tex]

Momentum of soccer ball = 6.88 [tex]\frac{kg m}{s}[/tex]

momentum of soccer ball is greater than that of tennis ball.

Explanation:

For table tennis ball,

Momentum of tennis the ball is given by,

Momentum = mass × volume

Momentum =  0.003 × 16

Momentum = 0.048 [tex]\frac{kg m}{s}[/tex]

For table soccer ball,

Momentum of the soccer ball is given by,

Momentum = mass × volume

Momentum =  0.43 × 16

Momentum = 6.88 [tex]\frac{kg m}{s}[/tex]

Thus, momentum of soccer ball is greater than that of tennis ball.

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