The slope-intercept form of the line that passes through the points (-2,8) and (1,2) is y=-2x+4
Step-by-step explanation:
Given:
Points(x,y)= )= (-2,8)
Points(x1,y1)= (1,2)
To find:
Equation in slope-intercept form=?
Solution:
The slope intercept form of a line is y= mx + b
Where m= the slope
STEP 1: Finding the slope value
[tex]\bold{\text { slope } =\frac{y-y 1}{x-x 1}}[/tex]
Substituting the points in the formula we get,
[tex]\text {slope, } \quad m=\frac{2-8}{1-(-2)}[/tex]
[tex]\text {slope, } \quad m=\frac{-6}{3}[/tex]
[tex]\text { slope, } \quad m=-2[/tex]
STEP 2: Finding the value of b
Substituting the slope value in the equation we have
y=mx+b,
y= -2(x)+b
y= -2(x) + b
substituting x and y from the points given,
8=-2(-2) + b
8=4+b
8-4=b
b =4
STEP 3: Formation of slope intercept equation
Substituting b and m in the equation of slope we get,
y= mx + b
y= -2x+4.
